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求极限:lim(x^2*sinx-2x^3)/(x^3+2x^4) 当x趋向于0
人气:341 ℃ 时间:2020-05-09 17:43:41
解答
lim(x→0) (x^2*sinx-2x^3)/(x^3+2x^4)
=lim(x→0) (sinx-2x)/(x+2x^2) (0/0)
= lim(x→0) (cosx-2)/(1+2x)
=-1
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