解方程(12x-10)/(4x-3)+(32x-34)/(8x-9)=(24x-23)/(8x-7)+(16x-19)/(4x-5)
人气:332 ℃ 时间:2020-05-10 13:51:14
解答
(12x-10)/(4x-3)+(32x-34)/(8x-9)=(24x-23)/(8x-7)+(16x-19)/(4x-5)
[3-1/(4x-3)]+[4+2/(8x-9)]=[3-2/(8x-7)]+[4+1/(4x-5)]
2/(8x-9)-1/(4x-3)=1/(4x-5)-2/(8x-7)
3/[(8x-9)(4x-3)]=3/[(4x-5)(8x-7)]
(4x-5)(8x-7)=(8x-9)(4x-3)
32x^2-68x+35=32x^2-60x+27
8x=8
x=1
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