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求计算题:cos315°+sin(-30°)+sin135°+cos480°
人气:334 ℃ 时间:2020-09-09 21:22:29
解答
=cos(360°-45°)+sin(-30°)+sin(180°-45°)+cos(360°+120°)
=cos(-45°)+sin(-30°)-sin(-45°)+cos120°
=cos45°-sin30°+sin45°+cos(180°-60°)
=cos45°-sin30°+sin45°-cos60°
结果是根号2减1
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