(a²+b²+2)/2-(a²-2b²+1)/3=[3(a²+b²+2)-2(a²-2b²+1)]/6=(3a²+3b²+6-2a²+4b²-2)/6=(a²+7b²+4)/6>0∵a²+7b²+4>0∴(a&sup...