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数学
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y=2x/(5x+1) .:x大于等于 0 的值域.
人气:377 ℃ 时间:2020-02-03 12:46:25
解答
y=2x/(5x+1)
=(2x+2/5-2/5)/(5x+1)
=2/5*(1-1/(5x+1))
当x≥0时,
5x+1≥1,
0<1/(5x+1)≤1,
-1≤-1/(5x+1<0,
0≤1-1/(5x+1)<1,
所以0≤y<2/5,
即y=2x/(5x+1) .x大于等于 0 的值域为【0,2/5).
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