已知m²+m-1=0,求m³+2m²+3的值
人气:486 ℃ 时间:2020-04-13 01:07:31
解答
使用逐次降幂法
先将原式两边同时×m
得m³=-m²+m
则后式为-m²+m+2m²+3=m²+m+3
然后又有原式得,m²=1-m
代入m²+m+3得1-m+m+3=4
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