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若1<x<4,化简根号(16-8x+x²)-根号(x²-2x+1)
人气:384 ℃ 时间:2019-11-09 00:23:57
解答
根号(16-8x+x²)-根号(x²-2x+1)
=√﹙x-4)²-√﹙x-1)²
=│x-4│-│x-1│
=4-x-(x-1)
=5-2x
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