用戴维南定理求图示电路中的电流 I.
已知R1 = R3 = 2欧, R2= 5欧,
R4= 8欧, R5=14欧, E1= 8V,
E2= 5V, IS= 3A.
断开R4,电路左、右两边是独立回路,R5 没有电流通过,E1、E2 负极电位相等,设为参考电位：Va = E1 * R3 / (R1+R3) = 4 VVb = E2 - Is * R2 = - 10 VUab = Va - Vb = 14 V Rab = R1//R3 + R5 + R2 = 20 ΩI = Uab ...
