如图,在△ABC中,∠ACB=90°,AB=根号8,BC=根号2,求斜边上的高过点C作CD⊥AB∵∠ACB=90∴AC＝√（AB²-BC²）＝√（8-2）＝√6∴S△ABC＝AC×BC/2＝√6×√2/2＝√3∵CD⊥AB∴S△ABC＝AB×CD/2＝√8×CD/2∴√...