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先化简,再求值(x-y/x+y)^2÷(y-x/x^2+2xy+y^2)^2*1/x+y,其中x=-4,y=1
人气:435 ℃ 时间:2020-06-14 14:11:56
解答
原式=(x-y)²/(x+y)²(x+y)^4/(x-y)²*1/(x+y)
=x+y
=-3
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