>
数学
>
已知{a
n
}为等差数列,a
1
+a
3
+a
5
=105,a
2
+a
4
+a
6
=99,则a
20
等于( )
A. -1
B. 1
C. 3
D. 7
人气:121 ℃ 时间:2019-10-15 08:31:09
解答
由已知得a
1
+a
3
+a
5
=3a
3
=105,
a
2
+a
4
+a
6
=3a
4
=99,
∴a
3
=35,a
4
=33,∴d=a
4
-a
3
=-2.
∴a
20
=a
3
+17d=35+(-2)×17=1.
故选B
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