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设A是四阶方阵,且|A|=1/3,则|A^-1|=3,|3A*-4A^-1|=?
人气:401 ℃ 时间:2020-06-25 11:55:02
解答
|A^-1| = 1/|A| = 3.
又因为 A* = |A|A^-1 = (1/3)A^-1
所以 |3A*-4A^-1|
= |A^-1 - 4A^-1|
= | - 3A^-1|
= (-3)^4 |A^-1|
= 3^4 * 3
= 3^5
= 243
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