（4y-3）（3y-1）=6分之25
12y²-9y-4y+3-25/6=0
12y²-13y-7/6=0
72y²-78y-7=0
(12y+1)(6y-7)=0
12y+1=0 6y-7=0
∴y₁=-1/12
y₂=7/6