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因式分解:(c²-b²+d²-a²)²-4(ab-cd)²
人气:316 ℃ 时间:2020-05-16 02:31:26
解答
(c²-b²+d²-a²)²-4(ab-cd)²
=[(c²-b²+d²-a²)+2(ab-cd)][(c²-b²+d²-a²)-2(ab-cd)]
=[(c²-2cd+d²)-(a²-2ab+b²)][(c²+2cd+d²)-(a²+2ab+b²)]
=[(c-d)²-(a-b)²][(c+d)²-(a+b)²]
=(c-d+a-b)(c-d-a+b)(c+d+a+b)(c+d-a-b)
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