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[6(x+2)^2+12(x+2)(x-2)-18(x+2)(x-1)]\6(x+2)计算
人气:287 ℃ 时间:2020-10-01 18:33:50
解答
[6(x+2)^2+12(x+2)(x-2)-18(x+2)(x-1)]\6(x+2)
=﹛6﹙x+2﹚[﹙x+2+2﹙x-2﹚-3﹙x-1﹚]﹜/6﹙x+2﹚
=x+2+2﹙x-2﹚-3﹙x-1﹚
=x+2+2x-4-3x+3
=1
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