[6(x+2)^2+12(x+2)(x-2)-18(x+2)(x-1)]\6(x+2)
=﹛6﹙x＋2﹚[﹙x＋2＋2﹙x－2﹚－3﹙x－1﹚]﹜／6﹙x＋2﹚
=x＋2＋2﹙x－2﹚－3﹙x－1﹚
=x＋2＋2x－4－3x＋3
=1