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已知x+x的负一次=3,求x的平方减x的负二次方等于多少
人气:178 ℃ 时间:2019-12-01 14:19:40
解答
x+1/x=3
(x+1/x)^2=9
x^2+1/x^2+2=9
x^2+1/x^2=7
x^2+1/x^2-2=7-2
(x-1/x)^2=5
x-1/x=±√5
x^2-1/x^2
=(x+1/x)(x-1/x)
=3*√5
=3√5

x^2-1/x^2
=(x+1/x)(x-1/x)
=3*(-√5)
=-3√5
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