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(x²-2x³+1)-(-1+2x³+2x²)其中x=2 先化简,再求值
人气:288 ℃ 时间:2020-03-20 13:49:20
解答
(x²-2x³+1)-(-1+2x³+2x²)=x²-2x³+1+1-2x³-2x²=-x²-4x³+2
当x=2 时,原式=-2²-4×2³+2=-4-32+2=-34(5a²-3b²)-3(a²-b²)-(-b²),其中a=5,b=-35x²-(3y²+5x²)+(4y²+3xy),其中x=-1,y=1/3计算:2x²y+{2xy-[3x²y-2(-3x²y+2xy)]-4xy²} 速度~当a=5,b=-3时(5a²-3b²)-3(a²-b²)-(-b²)=5a²-3b²-3a²+3b²+b²=2a²+b²=2×5+(-3)²=10+9=19当x=-1,y=1/3时5x²-(3y²+5x²)+(4y²+3xy)=5x²-3y²-5x²+4y²+3xy=y²+3ay=(1/3)²+3×(-1)×1/3=1/9-1=-8/9 2x²y+{2xy-[3x²y-2(-3x²y+2xy)]-4xy²}=2x²y+2xy-3x²y-6x²y+4xy-4xy²=-7x²y+6xy-4xy²
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