(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)怎么算?_数学解答

(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)怎么算?

人气：159 ℃　时间：2020-04-02 14:07:33

解答

(x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x) ＝[(x-1)(x-4)(x-2)(x-3)]-(x^2-5x)^2-10(x^2-5x) =(x^2-5x+4)(x^2-5x+6)-(x^2-5x)^2-10(x^2-5x) ==[(x^2-5x)+4][(x^2-5x)+6]-(x^2-5x)^2-10(x^2-5x) =(x^2-5x)^2+10(x^...