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(40-x)^2+(50-x)^2=(40+x)^2怎么解
人气:309 ℃ 时间:2020-05-19 15:02:23
解答
(40-x)^2+(50-x)^2=(40+x)^2
(40-x)^2-(40+x)^2+(50-x)^2=0
[(40-x)-(40+x)][(40-x)+(40+x)]+(50-x)^2=0
(40-x-40-x)(40-x+40+x)+(50-x)^2=0
-2x*80+x^2-100x+2500=0
x^2-260x+2500=0
(x-250)(x-10)=0
x=250或x=10
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