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化简:cos(π/2+α)-tan(π/2-α)sin(π/2+α)
人气:476 ℃ 时间:2020-05-23 12:28:37
解答
cos(π/2+α)-tan(π/2-α)sin(π/2+α)
=-sinα-cotαcosα
=-sinα-(cosα/sinα)cosα
=-(sin²α+cos²α)/sinα
=-1/sinα
=-cscα
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