如果a^2+b^2/2ab=2,求代数式7ab/(a^2+b^2)+(3a^2+5ab+3b^2)/6ab的值_数学解答

如果a^2+b^2/2ab=2,求代数式7ab/(a^2+b^2)+(3a^2+5ab+3b^2)/6ab的值

人气：137 ℃　时间：2019-08-21 18:14:51

解答

(a^2+b^2)/2ab = 2
a^2+b^2 = 42ab
7ab/(a^2+b^2)+(3a^2+5ab+3b^2)/6ab
=7ab/(a^2+b^2) + [3(a^2+b^2)+5ab]/6ab
=7ab/(4ab)+(12ab+5ab)/(6ab)
=7/4 +17/6
=55/12