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sin4/3π×cos5/6π×tan(-4/3π)
人气:357 ℃ 时间:2020-08-06 03:58:32
解答
sin4/3π×cos5/6π×tan(-4/3π)
=sin(π+ π/3)×cos(π- π/6)×[-tan(π/3 +π)]
=-sin(π/3)×[-cos(π/6)]×[-tan(π/3)]
=-(根号3)/2 × (根号3)/2 × 根号3
=-3(根号3)/4
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