解方程(6x+12)/(x^2+4x+4) + (x^2-4x+4)/(x^2-4) =(x^2-4)/(x^2-4x+4)_数学解答

解方程(6x+12)/(x^2+4x+4) + (x^2-4x+4)/(x^2-4) =(x^2-4)/(x^2-4x+4)

人气：131 ℃　时间：2020-03-24 23:08:56

解答

(6x+12)/(x²+4x+4) + (x²-4x+4)/(x²-4) =(x²-4)/(x²-4x+4)
6(x+2)/(x+2)²+(x-2)²/(x-2)(x+2)=(x-2)(x+2)/(x-2)²
6/(x+2)+(x-2)/(x+2)=(x+2)/(x-2)
6(x-2)+(x-2)²=(x+2)²
(x-2)(4+x)=(x+2)²
-8x+x²+4x-2x=x²+4x+4
-10x=4
x=-2/5