AlCl3 + 3NaOH = Al(OH)3↓+3NaCl
133.5 120 78
20g×26.7﹪ 0.075×2×40
=5.34g =6g X
从上面关系可以判断出NaOH不足,那么比例可以写成
120/6 g=78/X
X=3.9 g