> 数学 >
x4次方+8x²-9因式分解--------------------已知1/a+1/b=1/6,1/b+1/c=1/9,1/a+1/c=1/15,则abc/ab+ac+bc=-------
人气:187 ℃ 时间:2020-05-15 06:48:14
解答
1.x^4+8x^2-9=x^4-1+8x^2-8=(x^2+1)(x^2-1)+8(x^2-1)=(x+1)(x-1)(x^2+9)2.1/a+1/b=1/61/b+1/c=1/91/a+1/c=1/15三式相加得:2(1/a+1/b+1/c)=1/6+1/9+1/15=31/90即:1/a+1/b+1/c=31/180通分得:(ab+bc+ca)/(abc)=31/18...
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版