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八年级下册数学分式1/(a-1)(a-2)+1/(a-2)(a-3)+1(a-3)(a-4)+.+1(a-9)(a-10)结果是多少
人气:418 ℃ 时间:2020-06-17 16:06:13
解答
1/(a-1)(a-2)+1/(a-2)(a-3)+1(a-3)(a-4)+.+1(a-9)(a-10)
=1/(a-2)-1/(a-1)+1/(a-3)-1/(a-2)+.1/(a-10)-1/(a-9)
=1/(a-10)-1/(a-1)
=9/(a-10)(a-1)
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