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分式约分题目:
①a²+a-2分之-a²+2a-1 ②a²b²+2ab-15分之2a³b四次方-6a²b立方
人气:411 ℃ 时间:2020-03-28 10:31:40
解答
原式=-(a^2-2a+1)/(a^2+a-2) = -(a-1)^2/(a+2)(a-1) = -(a-1)/(a+2)
原式=(2a^3b^4-6a^2b^3)/(a^2b^2+2ab-15)= 2a^2b^3(ab- 3)/(ab+1)^2-16 = 2a^2b(ab- 3)/(ab+1+4)(ab+1-4) = 2a^2b(ab^3- 3)/(ab+5)
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