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x^2*cosx,如何求原函数?
人气:468 ℃ 时间:2020-10-01 13:08:06
解答
∫(x^2)cosxdx
=∫(x^2)dsinx
=(x^2)sinx-∫sinxd(x^2)
=(x^2)sinx-2∫xsinxdx
=(x^2)sinx+2∫xdcosx
=(x^2)sinx+2xcosx-2∫cosxdx
=(x^2)sinx+2xcosx-2sinx+C
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