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分式的乘除:(1)(x+y/x-y)*(1/(x+y)²)
(2)(a-b/a²+ab)/(a²+ab)÷[(ab-a²)/(a²b²-a的四次方)]
(3)(x²+7x-8)/(4x-x³ )*(x²-4)/3x+24
(4)(x²+2xy+y²/xy-y²)÷(xy+y²/x²-2xy+y²)
人气:316 ℃ 时间:2020-10-01 22:47:49
解答
(1)原式=1/x²-y²
(2)原式=a-b
(3)原式=1-x/3x
(4)原式=x²-y²/y²
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