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1/a-1/b=3,求(3a+4ab-3b)/(a-2ab-b)的值
人气:384 ℃ 时间:2020-03-21 17:09:57
解答
1/a-1/b=3
(b-a)/(ab)=3
b-a=3ab
a-b=-3ab
(3a+4ab-3b)/(a-2ab-b)
=[3(a-b)+4ab]/[(a-b)-2ab]
=(-9ab+4ab)/(-3ab-2ab)
=(-5ab)/(-5ab)
=1
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