已知y1=2x+8,y2=6-2x (1)当x取何值时,y1=y2? (2)当x取何值时,y1比y2小10
人气:360 ℃ 时间:2020-06-02 16:33:04
解答
(1)
2x+8=6-2x
4x=-2
x=-2分之1
(2)
2x+8+10=6-2x
2x+18=6-2x
4x=-12
x=-3
推荐
- 已知y1=2x+8,y2=6-2x. (1)当x取何值时,y1=y2; (2)当x取何值时,y1比y2小5.
- 已知y1=5x-8,y2=12x+6当x取何值时,y1-1/3y2=2x
- 已知y1=5x-8,y2=12x+6,当x取何值时1/2y1-1/3y2=2x
- 已知y1=5x-8,y2=12x+6,当x取何值时,y1-1/3y2=2x?
- 一次函数y1=3x+3与y2=-2x+8在同一直角坐标系内的交点坐标为(1,6).则当y1>y2时,x的取值范围是_.
- There are many things we need to know that we do not learn at school.For example,英语短文
- 在等差数列中a1=-4,a8=-18,n=8求Sn
- 实数x,y满足{x+2y-4+丨x+2y-4丨≤6,1≤x≤5,1≤y≤3},求u=(x^2+y^2)/xy的取值范围!
猜你喜欢