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约分(1) -x-1÷x²+2x+1 (2)4m²n²÷m²n²-4mn+4
人气:470 ℃ 时间:2020-09-29 10:53:01
解答
(-x-1)÷(x²+2x+1)
=-(x+1)÷(x+1)²
=-1/(x+1)
(4-m²n²)÷(m²n²-4mn+4)
=(4-m²n²)/(m²n²-4mn+4)
=-(m²n²-4)/(m²n²-4mn+4)
=-(mn-2)(mn+2)/(mn-2)²
=-(mn+2)/(mn-2)
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