1f(x)=2sinx乘cosx+2cos²x-1=sin2x+cos2x=√2(√2/2sin2x+√2/2cos2x)=√2sin(2x+π/4)f(x)最大值为√22∵点p(-3,4)在角α的终点上x=-3,y=4,r=5∴cosa=x/r=-3/5f(a+π/8)=√2sin[2(a+π/8)+π/4]=√2sin(2a+π/...