(x+3)/(x+4)+(x-1)/6=(7x+1)/12去分母,各项都乘以12（x+4）得12(x+3)+2(x+4)(x-1)=(x+4)(7x+1)12x+36+(2x+8)(x-1)=7x²+x+28x+412x+36+2x²-2x+8x-8=7x²+x+28x+45x²+11x-24=0解得x1=(-11+√601)/1...