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数学
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已知a是锐角且cos^4a-sin^4a=3/5,求sin2a
(2)
(sin^2a+3sinacosa-cos^2a)/(2sin^2a+cos^2a)的值
人气:343 ℃ 时间:2020-02-06 00:09:20
解答
cos^4a-sin^4a=3/5
(cos^2a-sin^2a)(cos^2a-sin^2a)=3/5
1*(cos^2a-sin^2a)=3/5
cos^2a-sin^2a=3/5
cos2a=3/5
a是锐角,∴2a∈(0,π)
∴sin2a = √{1- (sin2a)^2} = √{1- (3/5)^2} = 4/5
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