54km/h=15m/s汽车在4s内行驶的距离为s1=v1t=15m/s×4s=60m鸣笛声在4s内传播的总路程s2=v2t=340m/s×4s=1360m司机鸣笛时离山的距离为s=s1+s22=60m+1360m2=710m．此时汽车离高山的距离：s′=710m-60m=650m．答：司机听...