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已知abc=1,求(a/ab+a+1)+(b/bc+b+1)+(c/ac+c+1).
人气:493 ℃ 时间:2020-03-23 08:00:12
解答
a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)
=a/(ab+a+1)+ab/(abc+ab+a)+abc/(abac+abc+ab)
=a/(ab+a+1)+ab/(1+ab+a)+1/(a+1+ab)
=(ab+a+1)/(ab+a+1)
=1
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