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计算
(1)(−
1
2
)−123×0.125+(
3−27
−2012)0

(2)(
−a
b
)2÷(
2a2
5b
)2
a
5b

(3)
m+2n
n−m
+
n
m−n
2n
n−m

(4)(
x
x−y
2y
x−y
)•
xy
x−2y
÷(
1
x
+
1
y
)
人气:242 ℃ 时间:2020-05-22 07:30:21
解答
(1)原式=-2+8×0.125+1=-2+1+1=0;(2)原式=a2b2÷4a425b2•a5b=a2b2•25b24a2•a5b=5a4b;(3)原式=m+2nn−m-nn−m-2nn−m=m+2n−n−2nn−m=m−nn−m=-1;(4)原式=x−2yx−y•xyx−2y÷x+yxy=x−2yx−y•xyx...
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