0.01mol/L×0.1L |
0.001mol/L |
故答案为:900;
(2)pH=12 的NaOH溶液中氢氧根离子浓度是0.01mol/L,pH=11的氢氧化钠溶液中氢氧根离子浓度是0.001mol/L,pH=10的氢氧化钠溶液中氢氧根离子浓度是0.0001mol/L,
设加入pH=10的NaOH溶液体积是V2,
c1V1+c2V2=c3(V1+V2)=0.01mol/L×0.1L+0.0001mol/L×V2=0.001mol/L(0.1+V2),
V2=1L=1000mL,
故答案为:1000;
(3)0.008mol/L HCl溶液中氢离子浓度为0.008mol/L,设加入盐酸的体积为V,
c(OH-)=
0.01mol/L×0.1L−0.008mol/LL×V |
0.1L+V |
解得:V=100mL.
故答案为:100.