f(x)=sin(2x+π/6)+2(sinx)^2=根号3*sinx*(根3/2*cosx+1/2*sinx)+1/2=2sinx*sin(x+pi/3)+1/2=cos(-pi/3)-cos(2x+pi/3)+1/2=1-cos(2x+pi/3).(1)T=2pi/2=pi(2)最大值为2,当取得最大只是2x+pi/3=2kpi-pi,即x=2kpi-4pi/3...