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数学
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(101+103+…+199)-(90+92+…+188)=______.
人气:112 ℃ 时间:2019-11-15 03:26:24
解答
解法一:(101+103+…+199)-(90+92+…+188)=(101+199)×[(199-101)÷2+1]÷2-(90+188)×[(188-90)÷2+1]÷2,=300×50÷2-278×50÷2,=(300-278)×25,=22×25,=550.解法二:(101+103+…+199)-(9...
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