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如何证明logaM/logaN等于logbM/logbN
人气:492 ℃ 时间:2020-09-17 17:41:40
解答
提示:用换底公式.
证:
loga(m)/loga(n)
=(lgm/lga)/(lgn/lga)
=lgm/lgn
=logn(m)
logb(m)/logb(n)
=(lgm/lgb)/(lgn/lgb)
=lgm/lgn
=logn(m)
loga(m)/loga(n)=logb(m)/logb(n)
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