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设二元函数z=sin(x-y),求αz/αy,αy/αz,dz
人气:316 ℃ 时间:2019-12-10 09:19:27
解答
∂z/∂x=cos(x-y)
∂z/∂y=-cos(x-y)
dz=∂z/∂x*dx+∂z/∂y*dy
=cos(x-y)dx-cos(x-y)dy
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