> 数学 >
计算:
(1)(x+1)÷(2+
1+x2
x
);  
(2)(1-
a2+8
a2+4a+4
)÷
4a−4
a2+2a
人气:245 ℃ 时间:2020-02-04 00:32:41
解答
(1)原式=)(x+1)÷
x2+2x+1
x

=(x+1)×
x
(x+1)2

=
x
x+1

(2)原式=
a2+4a+4−a2−8
(a+2)2
×
a(a+2)
4(a−1)

=
4(a−1)
a+2
×
a
4(a−1)

=
a
a+2
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