求4m^2+9n^2+4m+6n+10的最小值
人气：310 ℃ 时间：2020-01-29 23:07:08
解答
4m^2+9n^2+4m+6n+10
=4m²+4m+1+9n²+6n+1+8
=(2m+1)²+(3n+1)²+8
∴4m^2+9n^2+4m+6n+10的最小值是8
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