(ab+a+1)/a+(bc+b+1)/b+(ac+c+1)/c=(abc+ac+c)/ac+(abc+ab+a)/ab+(ac+c+1)/c=(ac+c+1)/ac+(ab+a+1)/ab+(ac+c+1)/c=(ac+c+1)/ac+(abc+ac+c)/abc+(ac+c+1)/c=(ac+c+1)/ac+(ac+c+1)/1+(ac+c+1)/c=(ac+c+1)/(ac+c+1)=1