(x-1)²=(3-2x)²
(x-1)²-(3-2x)²=0
[(x-1)+(3-2x)][(x-1)-(3-2x)]=0
(2-x)(3x-4)=0
(x-2)(3x-4)=0
x1=2,x2=4/3
明白请采纳,
有新问题请求助,