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lim (cosx-sinx)/cos2x x→π/4
人气:337 ℃ 时间:2019-12-21 15:06:17
解答
(cosx-sinx)/cos2x=(cosx-sinx)/(cos^2x-sin^2x)=1/(sinx+cosx)
lim (cosx-sinx)/cos2x x→π/4=√2/2
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