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(3∕2)的9次方×(8∕9)的10次方×(3∕4)的11次方
人气:325 ℃ 时间:2019-10-11 18:47:29
解答
[(3/2)^9] × [(8/9)^10] × [(3/4)^11]=[(3^9)/(2^9)] × [(8^10)/(9^10)] × [(3^11)/(4^11)]=[(3^9)/(2^9)] × {[(2^3)^10]/[(3^2)^10]} × {(3^11)/[(2^2)^11]}=[(3^9)/(2^9)] × {[2^(3×10)]/[3^(2×10)]} × ...
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