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1-(a-(1-a)分之一)的平方÷(a的平方-2a+1)分之(a方-a+1)
人气：263 ℃　时间：2020-04-19 12:53:14
解答
1-[a-1/(1-a)]²÷ (a²-a+1)/(a²-2a+1)
=1-[(a²-a+1)/(a-1)]²÷[(a²-a+1)/(a-1)²]
=1-(a²-a+1)²/(a-1)²×(a-1)²/(a²-a+1)
=1-(a²-a+1)
=-a²+a
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